-16x^2+80x+5=30

Solution for -16x^2+80x+5=30 equation:

-16x^2+80x+5=30

We move all terms to the left:

-16x^2+80x+5-(30)=0

We add all the numbers together, and all the variables

-16x^2+80x-25=0

a = -16; b = 80; c = -25;
Δ = b2-4ac
Δ = 802-4·(-16)·(-25)
Δ = 4800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4800}=\sqrt{1600*3}=\sqrt{1600}*\sqrt{3}=40\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-40\sqrt{3}}{2*-16}=\frac{-80-40\sqrt{3}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+40\sqrt{3}}{2*-16}=\frac{-80+40\sqrt{3}}{-32}
$